7(a+5[b+2(2a+3b)])=

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Solution for 7(a+5[b+2(2a+3b)])= equation:


Simplifying
7(a + 5[b + 2(2a + 3b)]) = 0
7(a + 5[b + (2a * 2 + 3b * 2)]) = 0
7(a + 5[b + (4a + 6b)]) = 0

Reorder the terms:
7(a + 5[4a + b + 6b]) = 0

Combine like terms: b + 6b = 7b
7(a + 5[4a + 7b]) = 0
7(a + [4a * 5 + 7b * 5]) = 0
7(a + [20a + 35b]) = 0

Combine like terms: a + 20a = 21a
7(21a + 35b) = 0
(21a * 7 + 35b * 7) = 0
(147a + 245b) = 0

Solving
147a + 245b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-245b' to each side of the equation.
147a + 245b + -245b = 0 + -245b

Combine like terms: 245b + -245b = 0
147a + 0 = 0 + -245b
147a = 0 + -245b
Remove the zero:
147a = -245b

Divide each side by '147'.
a = -1.666666667b

Simplifying
a = -1.666666667b

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